affordable tomcat servlet

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affordable tomcat servlet

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affordable tomcat servlet affordable tomcat servlet out.println("n["+i+"] = " + n[i]); } boolean sorted = false; // sort the array while (!sorted) { sorted = true; for (int i=0; i < 9; i++) { if (n[i] > n[i+1]) { int temp = n[i]; n[i] = n[i+1]; n[i+1] = temp; sorted = false; } } } // print the sorted array System.out.println(); System.out.

affordable tomcat servlet println("After sorting:"); for (int i = 0; i < 10; i++) { System.out.println("n["+i+"] = " + n[i]); } }}In this case we have sorted the array in ascending order, smallest element first. It would be easy to change this to sort in descending order. Catching ExceptionsDo you remember this code?// This is the Hello program in Java class Hello { public static void main (String args[]) { /* Now let's say hello */ System.

affordable tomcat servlet out.print("Hello "); System.out.println(args[0]); }}Do you remember what happened when you ran the program without giving it any command line arguments? The runtime system generated an exceptionException in thread "main" java.lang.

affordable tomcat servlet ArrayIndexOutOfBoundsException at Hello.main(C:\javahtml\Hello.java:7)What happened was that since we didn't give Hello any command line arguments there wasn't anything in args[0]. Therefore Java kicked back this not too friendly error message about an "ArrayIndexOutOfBoundsException."Previously we fixed this problem by testing the length of the array before we tried to access its first element.

affordable tomcat servlet

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affordable tomcat servlet