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web hosting solution web hosting solution You might think that we should test for i being less than or equal to the number of arguments; but remember that we began counting at zero, not one.Finally we have the increment step, i=i+1. This is executed at the end of each iteration of the loop. Without this we'd continue to loop forever since i would always be less than args.length.

web hosting solution (unless, of course, args.length were less than or equal to zero. When would this happen?).Sidebar: Why Algebra teachers hate Basic and aren't that fond of CThe statement i=i+1 drives algebra teachers up the wall. It's an invalid assertion.

web hosting solution There isn't a number in the world for which the statement i=i+1 is true. In fact if you subtract i from both sides of that equation you get the patently false statement that 0 = 1. The trick here is that the symbol = does not imply equality. That is reserved for the double equals sign, ==. In almost all programming languages including Java a single equals sign is the assignment operator.

web hosting solution The notable exceptions are Pascal (and the Pascal derivatives Modula-2, Modula-3 and Oberon), Ada, and Eiffel where = does in fact mean equality and where := is the assignment operator. Math teachers are very fond of their equal sign and don't like to see it abused. This is one reason why Pascal is still the most popular language for teaching programming, especially in schools where the Computer Science department is composed mainly of math professors.Needless to say math professors hate languages like Basic where, depending on context, = can mean either assignment or equality. Exercises What happens now if we don't give the Hello program any command line arguments? We aren't testing the number of command line arguments anymore so why isn't an ArrayIndexOutOfBoundsException thrown? For math whizzes only: I lied.

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