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perl language perl language If it doesn't then the compiler assumes it's an integer. However when two numbers of different types such as integer and floating point are involved in a calculation on the right hand side of an equation, the compiler promotes the number of the weaker type to the stronger type before doing the calculation. What makes one type of number stronger than another? It's the ability to represent a broader spectrum of numbers. Since a byte can only represent 256 numbers it's weaker than a short which can stand for 65,535 different numbers including all the numbers a byte can represent. Similarly an int is stronger than a short.

perl language Floating point numbers are stronger than any integer type and doubles are the strongest type of all.Therefore we could have left all the small constants as integers and the program output would have been unchanged. However it is customary to put in decimal points to remind yourself and anyone else who may be unlucky enough to have to read your code, exactly what is going on.This applies to calculations that take place on the right hand side of an equal sign. The left hand side of the equals sign is a different story.

perl language In fact it's so different that programmers have given the different sides of the equals sign special names. The left-hand side is called an lvalue while the right hand side is called an rvalue. An rvalue is a calculated result and as specified above it takes on the strongest type of any number involved in the calculation. On the other hand the lvalue has a type that must be defined before it is used. That's what all those float fahr, celsius; statements are doing.

perl language Once the type of an lvalue is defined it never changes. Thus if we declare fahr to be an int, then on the left hand side of an equals sign fahr will always be an int, never a float or a double or a long.If you've been following along you may notice a problem here. What if the type on the left doesn't match the type on the right? e.g.

perl language

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